![]() Since the foreach is looping through a copy of the array, changing the original array will not alter the array which is being looped through, and thus, no conflict should occur. Don’t rely on the array pointer during or after the foreach without resetting it. Cng tng t nh loop for vy, chng ta li s dng splice() gii quyt: var arr 1, 2, 3, 4, 5. foreach has some side effects on the array pointer. javascript remove element from array in foreach. Now, we are going to do forEach to an array and if a condition matches, we will remove an element using splice and filter. ![]() The arr.forEach method allows to run a function for every element of the array. 2nd solution would be to iterate over the array index using standard for loop and decreasing the loop index i- whenever you found a match. So if we use splice to an array, then the original array will be mutated. splice ( 1, 1 ) // from index 1 remove 1 element alert ( arr ). Two solutions come to mind immediately: Push all non-matches in a new array, and at the end of forEach replace the original array with the new one. Here is a simple example using splice with reduce. filter is not a mutable method, but splice is a mutable method. You could use reduce to go through the array with splice. var mainArr 'jan', 'feb', 'apple' var exArr 'feb', 'apple' removeGivenArr (mainArr, exArr. the commented code is working as expected but when I try to use similar with foreach, the code is not working as expected. forEach function gets stopped after the splice operation. Unless the array is referenced, foreach operates on a copy of the specified array and not the array itself. We can mutate an array using splice and filter. array splice not working as expected inside the function.
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